2^(x+2)=1/32

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Solution for 2^(x+2)=1/32 equation: 



2^(x+2)=1/32

We move all terms to the left:

2^(x+2)-(1/32)=0

We add all the numbers together, and all the variables

2^(x+2)-(+1/32)=0

We get rid of parentheses

2^(x+2)-1/32=0

We multiply all the terms by the denominator


(2^(x+2))*32-1=0

We move all terms containing x to the left, all other terms to the right

(2^(x+2))*32=1

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